3[x+(2x-1)]=-1(x+5)

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Solution for 3[x+(2x-1)]=-1(x+5) equation:


Simplifying
3[x + (2x + -1)] = -1(x + 5)

Reorder the terms:
3[x + (-1 + 2x)] = -1(x + 5)

Remove parenthesis around (-1 + 2x)
3[x + -1 + 2x] = -1(x + 5)

Reorder the terms:
3[-1 + x + 2x] = -1(x + 5)

Combine like terms: x + 2x = 3x
3[-1 + 3x] = -1(x + 5)
[-1 * 3 + 3x * 3] = -1(x + 5)
[-3 + 9x] = -1(x + 5)

Reorder the terms:
-3 + 9x = -1(5 + x)
-3 + 9x = (5 * -1 + x * -1)
-3 + 9x = (-5 + -1x)

Solving
-3 + 9x = -5 + -1x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'x' to each side of the equation.
-3 + 9x + x = -5 + -1x + x

Combine like terms: 9x + x = 10x
-3 + 10x = -5 + -1x + x

Combine like terms: -1x + x = 0
-3 + 10x = -5 + 0
-3 + 10x = -5

Add '3' to each side of the equation.
-3 + 3 + 10x = -5 + 3

Combine like terms: -3 + 3 = 0
0 + 10x = -5 + 3
10x = -5 + 3

Combine like terms: -5 + 3 = -2
10x = -2

Divide each side by '10'.
x = -0.2

Simplifying
x = -0.2

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